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Re: [ptlong2] Pendulum fall speed:
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Rudmin
Sep 1, 2010, 3:25 PM
Views: 20730
Registered: Mar 29, 2009
Posts: 606
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s and T are quite linearly related. You solve one and you have the other. The problem is that the centrifugal component of T is a function of v. That is m*v^2/(L+s). Simple enough to solve recursively, but it puts a crimp in your solution. To run it through some simple numbers. Let's say 10 metres of rope with a 100 kg climber and a stiffness of 24 kN per metre. (that's assuming that only the 10 metres of rope is being used). What I get is a velocity of about 50.2 km/hour and a rope tension of about 3kN. In essence, the rope stretch does next to nothing. If we take a quarter of the stiffness, as if you had almost a full rope length out, we get a velocity of 49.8 km/hour. So looks like no amount of climbing rope will help you in a pendulum.
(This post was edited by Rudmin on Sep 1, 2010, 3:26 PM)
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Post edited by Rudmin
() on Sep 1, 2010, 3:26 PM
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