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Climbing problem for math geniuses
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lena_chita
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Sep 21, 2006, 7:03 PM
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Climbing problem for math geniuses
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There are 6 climbers:

climber #1 warms up on 10s, wants to lead a few 11s and redpoint a specific 5.12

climber #2 can warm up on anything 5.7 and up, toprope or lead, wants to lead a bunch of .10s and .11s, and maybe get on that .12 that climber #1 is eyeing.

climber #3 can theoretically lead some easy 5.10s and will definitely top-rope .10s and .11s, but this person is having "bad lead head" issues and would prefer to lead all 5.7s, then all 5.8s, then all 5.9s in the area, before leading .10s

climber #4 will gamely toprope up to 5.10, but can only lead 5.7, though could maybe be persuaded to get on 5.8.

climber #5 can probably toprope 5.10, skills unknown, technique nonexistent, but powers through stuff. Does not lead, Lead belay skills unknown, assume that he can't lead belay.

climber #6 won't be able to climb anything above 5.7-5.8, though will probably hang on the rope on any climb offered. Does not lead and lead-belay.


The 6 climbers go on a trip together. Splitting up is not an option. They go to an area that has
2x5.7s
1x5.8
3x5.9
more than 5 each 5.10s-5.12s, including the specific 5.12 that climber #1 has his heart set on.

They have 4 ropes but only 2 sets of 15 quickdraws in between them.

Asssume that it takes climber #4 and #6 twice as long to climb a route that climbers #1-2-3 lead, that climber #4 and #5 will declare themselves tired after 6 climbs and climber number 6 will do the same after 4 climbs

In what order should they climb so that each person gets to climb at least the number of climbs it takes them to get tired, and climbers 1-2-3 will get at least 8 climbs each?


:lol: :lol: :lol: Things that pop into your mind at 3 am when a child wakes you up after only 3 hours of sleep


Partner ewtotel


Sep 21, 2006, 7:19 PM
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http://www.tate.org.uk/...eynewman_midsize.jpg


climbindrummer


Sep 21, 2006, 8:01 PM
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In reply to:
There are 6 climbers:

climber #1 warms up on 10s, wants to lead a few 11s and redpoint a specific 5.12

climber #2 can warm up on anything 5.7 and up, toprope or lead, wants to lead a bunch of .10s and .11s, and maybe get on that .12 that climber #1 is eyeing.

climber #3 can theoretically lead some easy 5.10s and will definitely top-rope .10s and .11s, but this person is having "bad lead head" issues and would prefer to lead all 5.7s, then all 5.8s, then all 5.9s in the area, before leading .10s

climber #4 will gamely toprope up to 5.10, but can only lead 5.7, though could maybe be persuaded to get on 5.8.

climber #5 can probably toprope 5.10, skills unknown, technique nonexistent, but powers through stuff. Does not lead, Lead belay skills unknown, assume that he can't lead belay.

climber #6 won't be able to climb anything above 5.7-5.8, though will probably hang on the rope on any climb offered. Does not lead and lead-belay.


The 6 climbers go on a trip together. Splitting up is not an option. They go to an area that has
2x5.7s
1x5.8
3x5.9
more than 5 each 5.10s-5.12s, including the specific 5.12 that climber #1 has his heart set on.

They have 4 ropes but only 2 sets of 15 quickdraws in between them.

Asssume that it takes climber #4 and #6 twice as long to climb a route that climbers #1-2-3 lead, that climber #4 and #5 will declare themselves tired after 6 climbs and climber number 6 will do the same after 4 climbs

In what order should they climb so that each person gets to climb at least the number of climbs it takes them to get tired, and climbers 1-2-3 will get at least 8 climbs each?


:lol: :lol: :lol: Things that pop into your mind at 3 am when a child wakes you up after only 3 hours of sleep

#6 starts up the .10's that #1 wants to warm up on, so #1 skips right to the nearest 11a/b. #2 belays #6 up the .10, but #6 can't climb it so #2 is getting pissed at the near-constant hangdogging. #3 leads up a 5.9 while #5 belays. #4 eats a ham sammich and rags on #6's mother. #6 gets pissed, lowers off, and stalks off to the car. #1 and #3 go off to work the redpoint while #4 decides he "just wants to boulder a little". #2 and #5 decide to just stick to the 5.9s and do some laps 'cause #2 has decided today is a good day "to get in some ARCing" and he didn't really feel like it was "a 5.12 day anyway"...


jcr


Sep 21, 2006, 8:30 PM
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After long hours of carefully examining the problem I have come to the conclusion I cannot find an answer to it unless you respond to the following quandries....

WHY ARE THERE 6 CLIMBERS AND NOT 9???

WHY DO CLIMBERS 1-3 HAVE TO PUT UP WITH CLIMBERS 4-6, GIVEN THEIR EXPERIENCE????

WHY DONT THEY HAVE MORE GEAR????

WHERE THE KCUF IS THIS PLACE????

HOW DID THEY GET THERE???

WHY DO THE 1-3 CLIMBERS HAVE TO CLIMB 8 ROUTES EACH???

IF SOME CLIMBERS GET TIRED AFTER 4 TO 6 CLIMBS, WHY DID THEY GET INVITED???

WHAT ARE THEIR NAMES???

ARE THESE GUYS REALLY FRIENDS???

AM I ONE OF THE 6 CLIMBERS????

IS ONE OF THE CLIMBERS A GIRL???? IF SO, IS SHE HOOOT?????

WHY CANT THEY SPLIT UP??? WHAT IF SOMEONE HAS TO POOP???

IS THERE ANY TOILET PAPER???

HAVE THEY HAD ANY BREAKFAST???

ARE THESE GUYS ON WEED???

and most importantly....

DONDE ESTA JUAN????

________________________________________________

AND SERIOUSLY DUDE... YOU HAVE TOO MUCH TIME IN YOUR HANDS!

GO CLIMBING!


________
JC


jcr


Sep 21, 2006, 8:38 PM
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OH, AND EVERYBODY FEEL FREE TO ADD ANY MORE QUESTIONS YOU FEEL ARE IMPORTANT FOR THE IDEAL SOLVING OF THIS MOST INSIGHTFULL, INTERESTING, AND EDUCATIVE PROBLEM......


JC


qtm


Sep 21, 2006, 9:18 PM
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#1 & #2 go off and do their own thing with one rope and half the draws. They can swap leads if they want.

#3 leads 7, 7, 8, 9, 9, 9, 10 and 10. #4 cleans six of them, #3 cleans the last two when lowering since #4 can only climb six routes, and apparently doesn't *have* to lead any.

#3 leaves a rope on first 7, leaves another on second 7, climbs 8 with third rope. When #3 does goes for the 9, he pulls the rope from the first 7. For the second 9, he pulls the rope off the 2nd 7. They toprope directly through the chains.

#5 climbs with #6, although he climbs two more routes than #6.
#6 climbs 7, 7, 8, then flais on 9 and calls it a day, but still belays #5 on the other two 9's.

I think that works...


redlegrangerone


Sep 21, 2006, 9:29 PM
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Geeeeeeeeeez, you really have to wonder about Lena_Chica's climbing partners. :shock:


sed


Sep 21, 2006, 9:33 PM
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if everyone solos the gear shouldn't be a problem


trevzilla


Sep 21, 2006, 10:14 PM
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First off, I'd like to tell you that I am perfectly qualified to solve this problem, as I just got my B.S. in Mathematics. With that said, I have analyzed the problem, I have realized that a solution does exist, and therefore, I have moved on to the next problem.

:lol: :lol:


ihuang


Sep 21, 2006, 10:20 PM
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Sounds like a computer science problem. Try dynamic programming. Failing that, do an exhaustive search. Err... what are we trying to optimize again? :)


climbindrummer


Sep 21, 2006, 11:01 PM
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In reply to:
#1 & #2 go off and do their own thing with one rope and half the draws. They can swap leads if they want.

#3 leads 7, 7, 8, 9, 9, 9, 10 and 10. #4 cleans six of them, #3 cleans the last two when lowering since #4 can only climb six routes, and apparently doesn't *have* to lead any.

#3 leaves a rope on first 7, leaves another on second 7, climbs 8 with third rope. When #3 does goes for the 9, he pulls the rope from the first 7. For the second 9, he pulls the rope off the 2nd 7. They toprope directly through the chains.

#5 climbs with #6, although he climbs two more routes than #6.
#6 climbs 7, 7, 8, then flais on 9 and calls it a day, but still belays #5 on the other two 9's.

I think that works...

Wow... I'm impressed. Trophy for you, despite the fact you neglected to factor in who had the most heinous spandex. :)


the_climber


Sep 21, 2006, 11:38 PM
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Just so we are all on the same page.
We are talking about climbing at this crag right?

http://www.mountaineering-scotland.org.uk/.../cartoons/griff2.gif
:lol:


the_climber


Sep 21, 2006, 11:39 PM
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Oh, and ewtotel I think it's more like this:
http://os2.in.ru/...tin/image/OS2002.gif


lena_chita
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Sep 25, 2006, 3:50 PM
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:lol: :lol: :lol:


Now the actual answer:

Day 1: climbers 1-6 agree to meet at the crag on 2pm Friday. Getting there requires 7 hr drive.

Climbers 1,2 and 3 arrive at the crag at the planned time within 15 min of each other. Climbers 4-6 are carpooling and plan to leave "first thing in the morning" which morphs into 11 am, then 12 am, and turns into actual departure time of 1:30 p.m. 8^) Notified of this (thank God for cell phones!) and faced with the fact that it rained heavily in the morning, Climbers 1-3 abandon the original plan to go to the crag with 5.7s, go to 5.10-5.12 pumpfest area and climb there, but only get to climb 2 easy routes before dusk b/c it turns out the climber 3 has a "roof problem" in addition to 'leadhead problem" and the routes that look dry turn out to be quite sopingly wet in spots. So climbers 1-3 get pizza, set up tents and hope against hope for better weather the next day. Climber 4-6 arrive at campground on 10 pm :?

Night 1: it rains heavily for half of the night. Combined with previous day, it's a total of 6 inches :cry:

Day 2. Climbers 4 and 6 wake up floating in their shared tent that did not have a full fly and the one they neglected to put the vestibule on, head to the gas station for coffee and declare that they are leaving. Climber 5 jumps ship and declares that he is staying.

Climbers 1,2,3,5 hook up with their friends climbers 7 and 8 that stayed at the same campsite and head to the only remotely-climable area available under circumstances. Of course the entire horde of long-distance visitors desperate for SOME climbing heads there, too, so there are lines to get on anything dry. Climber 1 does not get on his coveted 5.12 b/c it looks wet. Climber 2 desides not to lead anything but has fun top-roping after climber 1. Climber 3 is having overhang problem as well as the roof problem and leaves after climbing one route, taking climber 5 with her. Climber 1 and 2 get to climb a couple of routes, observe the amount of mud on their children and with more rain in the forecast head back home a day early... :cry:


majid_sabet


Sep 26, 2006, 12:41 AM
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I say
" You only need to make one mistake, and its all over"


qtm


Sep 26, 2006, 2:02 PM
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In reply to:
I say
" You only need to make one mistake, and its all over"

I forgot to carry a one on a math test and only got a 95. Still it wasn't "all over".

I made a *big* mistake once, on the road, and spent 8 weeks in the hospital and almost lost a leg. I've got permanent damage and will always be in physical pain, but even then it's not "all over".

I only tied into my waist loop once, forgot to tie my leg loops. I realized it about 5' up and downclimbed and retied. I didn't die.

People make mistakes all the time, and they don't all die.


redlegrangerone


Sep 26, 2006, 2:26 PM
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Yes, not all of us die from our mistakes. But I will die happily someday knowing that good old Majid_Sabid will be around to write about it on rc.com.


lena_chita
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Sep 26, 2006, 2:38 PM
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majid_sabet wrote:
I say
" You only need to make one mistake, and its all over"



How did we arrive at that conclusion from the OP? Gosh, and here I was telling my child to "learn from his mistakes"! Bad bad Mommy, I should have said: You miss one word on that spelling test and it's over -- YOU DIE!!!!!!


healyje


Sep 26, 2006, 3:54 PM
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John Gill was a math teacher and quite aptly showed that all the rock climbing problems worth solving could be worked out on a swing set with four fingers.


jumpingrock


Sep 26, 2006, 3:55 PM
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In reply to:
John Gill was a math teacher and quite aptly showed that all the rock climbing problems worth solving could be worked out on a swing set with four fingers.

What was he doing with his other 6 fingers while on said swing set?


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